JQ (GET ID based on NAME)

The name of the pictureThe name of the pictureThe name of the pictureClash Royale CLAN TAG#URR8PPP

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I get a long list of such arrays

{
    "id": "byu6g6c4cjys5mdkg5znh8ju8c",
    "create_at": 1511875272294,
    "update_at": 1511875272294,
    "delete_at": 0,
    "display_name": "BMA",
    "name": "BMA",
    "description": "",
    "email": "aleksandar.ivanov@random.com",
    "type": "O",
    "company_name": "",
    "allowed_domains": "",
    "invite_id": "gdgz1tbxuinntx1fbr1ax7kehy",
    "allow_open_invite": false,
    "scheme_id": null
  }

I want to get by JQ only the ID where the name is BMA.
At the moment I parse ” jq -r ‘.[“name”]” and I can filter the output from curl by name and I will get “BMA” and also 100 other names, but I need to filter only the ID where name is =BMA.
Any ideas?

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    up vote
    1
    down vote

    favorite

    I get a long list of such arrays

    {
        "id": "byu6g6c4cjys5mdkg5znh8ju8c",
        "create_at": 1511875272294,
        "update_at": 1511875272294,
        "delete_at": 0,
        "display_name": "BMA",
        "name": "BMA",
        "description": "",
        "email": "aleksandar.ivanov@random.com",
        "type": "O",
        "company_name": "",
        "allowed_domains": "",
        "invite_id": "gdgz1tbxuinntx1fbr1ax7kehy",
        "allow_open_invite": false,
        "scheme_id": null
      }
    

    I want to get by JQ only the ID where the name is BMA.
    At the moment I parse ” jq -r ‘.[“name”]” and I can filter the output from curl by name and I will get “BMA” and also 100 other names, but I need to filter only the ID where name is =BMA.
    Any ideas?

    share|improve this question

      up vote
      1
      down vote

      favorite

      up vote
      1
      down vote

      favorite

      I get a long list of such arrays

      {
          "id": "byu6g6c4cjys5mdkg5znh8ju8c",
          "create_at": 1511875272294,
          "update_at": 1511875272294,
          "delete_at": 0,
          "display_name": "BMA",
          "name": "BMA",
          "description": "",
          "email": "aleksandar.ivanov@random.com",
          "type": "O",
          "company_name": "",
          "allowed_domains": "",
          "invite_id": "gdgz1tbxuinntx1fbr1ax7kehy",
          "allow_open_invite": false,
          "scheme_id": null
        }
      

      I want to get by JQ only the ID where the name is BMA.
      At the moment I parse ” jq -r ‘.[“name”]” and I can filter the output from curl by name and I will get “BMA” and also 100 other names, but I need to filter only the ID where name is =BMA.
      Any ideas?

      share|improve this question

      I get a long list of such arrays

      {
          "id": "byu6g6c4cjys5mdkg5znh8ju8c",
          "create_at": 1511875272294,
          "update_at": 1511875272294,
          "delete_at": 0,
          "display_name": "BMA",
          "name": "BMA",
          "description": "",
          "email": "aleksandar.ivanov@random.com",
          "type": "O",
          "company_name": "",
          "allowed_domains": "",
          "invite_id": "gdgz1tbxuinntx1fbr1ax7kehy",
          "allow_open_invite": false,
          "scheme_id": null
        }
      

      I want to get by JQ only the ID where the name is BMA.
      At the moment I parse ” jq -r ‘.[“name”]” and I can filter the output from curl by name and I will get “BMA” and also 100 other names, but I need to filter only the ID where name is =BMA.
      Any ideas?

      linux json jq javascript

      share|improve this question

      share|improve this question

      share|improve this question

      share|improve this question

      edited Nov 29 at 17:38

      Jeff Schaller

      37.4k1052121

      37.4k1052121

      asked Nov 29 at 17:32

      Denis Hristov

      173

      173

          1 Answer
          1

          active

          oldest

          votes

          up vote
          1
          down vote

          accepted

          jq

          You should be able to accomplish this with the following:

          jq '. | select (.name=="BMA") | .id'
          

          If name is BMA it will print id


          json

          json -c 'this.name === "BMA"' -a id
          

          share|improve this answer

          • 1

            That solved it !! Thank u so much
            – Denis Hristov
            Nov 29 at 17:45

          • Hello, I manage do it now , but I get this output though: jq: error: deposit/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: error: solutions/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: 2 compile errors Any ideas?
            – Denis Hristov
            Nov 29 at 18:23

          • @DenisHristov: Make sure you quote the names you are searching for as they are not defined variables. Should be select (.name=="deposit-solutions") for example.
            – Jesse_b
            Nov 29 at 18:25

          • I cannot quote the names output as it is from another API call and when I do “$test” it doesn’t recognize the variable. Any help here?
            – Denis Hristov
            Nov 29 at 18:30

          • You can try: jq ". | select (.name=="$test") | .id"
            – Jesse_b
            Nov 29 at 18:34

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          1 Answer
          1

          active

          oldest

          votes

          1 Answer
          1

          active

          oldest

          votes

          active

          oldest

          votes

          active

          oldest

          votes

          up vote
          1
          down vote

          accepted

          jq

          You should be able to accomplish this with the following:

          jq '. | select (.name=="BMA") | .id'
          

          If name is BMA it will print id


          json

          json -c 'this.name === "BMA"' -a id
          

          share|improve this answer

          • 1

            That solved it !! Thank u so much
            – Denis Hristov
            Nov 29 at 17:45

          • Hello, I manage do it now , but I get this output though: jq: error: deposit/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: error: solutions/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: 2 compile errors Any ideas?
            – Denis Hristov
            Nov 29 at 18:23

          • @DenisHristov: Make sure you quote the names you are searching for as they are not defined variables. Should be select (.name=="deposit-solutions") for example.
            – Jesse_b
            Nov 29 at 18:25

          • I cannot quote the names output as it is from another API call and when I do “$test” it doesn’t recognize the variable. Any help here?
            – Denis Hristov
            Nov 29 at 18:30

          • You can try: jq ". | select (.name=="$test") | .id"
            – Jesse_b
            Nov 29 at 18:34

          up vote
          1
          down vote

          accepted

          jq

          You should be able to accomplish this with the following:

          jq '. | select (.name=="BMA") | .id'
          

          If name is BMA it will print id


          json

          json -c 'this.name === "BMA"' -a id
          

          share|improve this answer

          • 1

            That solved it !! Thank u so much
            – Denis Hristov
            Nov 29 at 17:45

          • Hello, I manage do it now , but I get this output though: jq: error: deposit/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: error: solutions/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: 2 compile errors Any ideas?
            – Denis Hristov
            Nov 29 at 18:23

          • @DenisHristov: Make sure you quote the names you are searching for as they are not defined variables. Should be select (.name=="deposit-solutions") for example.
            – Jesse_b
            Nov 29 at 18:25

          • I cannot quote the names output as it is from another API call and when I do “$test” it doesn’t recognize the variable. Any help here?
            – Denis Hristov
            Nov 29 at 18:30

          • You can try: jq ". | select (.name=="$test") | .id"
            – Jesse_b
            Nov 29 at 18:34

          up vote
          1
          down vote

          accepted

          up vote
          1
          down vote

          accepted

          jq

          You should be able to accomplish this with the following:

          jq '. | select (.name=="BMA") | .id'
          

          If name is BMA it will print id


          json

          json -c 'this.name === "BMA"' -a id
          

          share|improve this answer

          jq

          You should be able to accomplish this with the following:

          jq '. | select (.name=="BMA") | .id'
          

          If name is BMA it will print id


          json

          json -c 'this.name === "BMA"' -a id
          

          share|improve this answer

          share|improve this answer

          share|improve this answer

          answered Nov 29 at 17:37

          Jesse_b

          11.5k23063

          11.5k23063

          • 1

            That solved it !! Thank u so much
            – Denis Hristov
            Nov 29 at 17:45

          • Hello, I manage do it now , but I get this output though: jq: error: deposit/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: error: solutions/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: 2 compile errors Any ideas?
            – Denis Hristov
            Nov 29 at 18:23

          • @DenisHristov: Make sure you quote the names you are searching for as they are not defined variables. Should be select (.name=="deposit-solutions") for example.
            – Jesse_b
            Nov 29 at 18:25

          • I cannot quote the names output as it is from another API call and when I do “$test” it doesn’t recognize the variable. Any help here?
            – Denis Hristov
            Nov 29 at 18:30

          • You can try: jq ". | select (.name=="$test") | .id"
            – Jesse_b
            Nov 29 at 18:34

          • 1

            That solved it !! Thank u so much
            – Denis Hristov
            Nov 29 at 17:45

          • Hello, I manage do it now , but I get this output though: jq: error: deposit/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: error: solutions/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: 2 compile errors Any ideas?
            – Denis Hristov
            Nov 29 at 18:23

          • @DenisHristov: Make sure you quote the names you are searching for as they are not defined variables. Should be select (.name=="deposit-solutions") for example.
            – Jesse_b
            Nov 29 at 18:25

          • I cannot quote the names output as it is from another API call and when I do “$test” it doesn’t recognize the variable. Any help here?
            – Denis Hristov
            Nov 29 at 18:30

          • You can try: jq ". | select (.name=="$test") | .id"
            – Jesse_b
            Nov 29 at 18:34

          1

          1

          That solved it !! Thank u so much
          – Denis Hristov
          Nov 29 at 17:45

          That solved it !! Thank u so much
          – Denis Hristov
          Nov 29 at 17:45

          Hello, I manage do it now , but I get this output though: jq: error: deposit/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: error: solutions/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: 2 compile errors Any ideas?
          – Denis Hristov
          Nov 29 at 18:23

          Hello, I manage do it now , but I get this output though: jq: error: deposit/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: error: solutions/0 is not defined at <top-level>, line 1: . | select (.name==deposit-solutions) | .id jq: 2 compile errors Any ideas?
          – Denis Hristov
          Nov 29 at 18:23

          @DenisHristov: Make sure you quote the names you are searching for as they are not defined variables. Should be select (.name=="deposit-solutions") for example.
          – Jesse_b
          Nov 29 at 18:25

          @DenisHristov: Make sure you quote the names you are searching for as they are not defined variables. Should be select (.name=="deposit-solutions") for example.
          – Jesse_b
          Nov 29 at 18:25

          I cannot quote the names output as it is from another API call and when I do “$test” it doesn’t recognize the variable. Any help here?
          – Denis Hristov
          Nov 29 at 18:30

          I cannot quote the names output as it is from another API call and when I do “$test” it doesn’t recognize the variable. Any help here?
          – Denis Hristov
          Nov 29 at 18:30

          You can try: jq ". | select (.name=="$test") | .id"
          – Jesse_b
          Nov 29 at 18:34

          You can try: jq ". | select (.name=="$test") | .id"
          – Jesse_b
          Nov 29 at 18:34

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